5b^2=63

Solution for 5b^2=63 equation:

5b^2=63

We move all terms to the left:

5b^2-(63)=0

a = 5; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·5·(-63)
Δ = 1260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1260}=\sqrt{36*35}=\sqrt{36}*\sqrt{35}=6\sqrt{35}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{35}}{2*5}=\frac{0-6\sqrt{35}}{10}
=-\frac{6\sqrt{35}}{10}
=-\frac{3\sqrt{35}}{5}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{35}}{2*5}=\frac{0+6\sqrt{35}}{10}
=\frac{6\sqrt{35}}{10}
=\frac{3\sqrt{35}}{5}
$